python mathutils change

quat * quat was returning the dot product (a float), rather then the cross product.
 Use BLI_math's mul_qt_qtqt() function.
This commit is contained in:
2010-08-02 00:08:01 +00:00
parent 2e7c8bbeec
commit c04850ec06
6 changed files with 27 additions and 81 deletions

View File

@@ -660,8 +660,9 @@ static PyObject *Quaternion_mul(PyObject * q1, PyObject * q2)
return NULL;
}
if(quat1 && quat2) { /* QUAT*QUAT (dot product) */
return PyFloat_FromDouble(dot_qtqt(quat1->quat, quat2->quat));
if(quat1 && quat2) { /* QUAT*QUAT (cross product) */
mul_qt_qtqt(quat, quat1->quat, quat2->quat);
return newQuaternionObject(quat, Py_NEW, NULL);
}
/* the only case this can happen (for a supported type is "FLOAT*QUAT" ) */
@@ -677,12 +678,19 @@ static PyObject *Quaternion_mul(PyObject * q1, PyObject * q2)
}
else { /* QUAT*SOMETHING */
if(VectorObject_Check(q2)){ /* QUAT*VEC */
float tvec[3];
vec = (VectorObject*)q2;
if(vec->size != 3){
PyErr_SetString(PyExc_TypeError, "Quaternion multiplication: only 3D vector rotations currently supported\n");
return NULL;
}
return quat_rotation((PyObject*)quat1, (PyObject*)vec); /* vector updating done inside the func */
if(!BaseMath_ReadCallback(vec)) {
return NULL;
}
copy_v3_v3(tvec, vec->vec);
mul_qt_v3(quat1->quat, tvec);
return newVectorObject(tvec, 3, Py_NEW, NULL);
}
scalar= PyFloat_AsDouble(q2);