31 lines
1.1 KiB
Python
31 lines
1.1 KiB
Python
'''
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This utility allows a python system to find a file in it's
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directory. To do this, you need to pass it a function object from
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a module in the correct directory. I know there must be a better
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way to do this, but I haven't seen it yet. Incidentally, the
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current directory should be _different_ from the module in which
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the function is contained, otherwise this function will go off into
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the root directory.
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Currently this has to be called with the current directory a directory
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other than the directory we're trying to find... need a better solution
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for this kind of thing... a python registry would be great :)
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NOTE: as of Python 1.5, this module should be obsolete! As soon as I
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have verified that all of my code is fixed, it will be moved to the unused
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directories.
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'''
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import os,sys
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def findourfile(function, filename):
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'''
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Given the function, return a path to the a file in the
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same directory with 'filename'. We also let the caller
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know if the file already exists.
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'''
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ourfilename = os.path.split(function.func_code.co_filename)[0]+os.sep+filename
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exists = os.path.exists(ourfilename)
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return (exists,ourfilename)
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