92 lines
2.2 KiB
C
92 lines
2.2 KiB
C
/**
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* $Id$
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*
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* ***** BEGIN GPL LICENSE BLOCK *****
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*
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* This program is free software; you can redistribute it and/or
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* modify it under the terms of the GNU General Public License
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* as published by the Free Software Foundation; either version 2
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* of the License, or (at your option) any later version.
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*
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* This program is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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* GNU General Public License for more details.
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*
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* You should have received a copy of the GNU General Public License
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* along with this program; if not, write to the Free Software Foundation,
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* Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA.
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*
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* The Original Code is Copyright (C) 2001-2002 by NaN Holding BV.
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* All rights reserved.
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*
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* The Original Code is: some of this file.
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*
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* ***** END GPL LICENSE BLOCK *****
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* */
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#include "BLI_math.h"
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/* WARNING: MSVC compiling hack for double_round() */
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#if (WIN32 || WIN64) && !(FREE_WINDOWS)
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/* from python 3.1 pymath.c */
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double copysign(double x, double y)
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{
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/* use atan2 to distinguish -0. from 0. */
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if (y > 0. || (y == 0. && atan2(y, -1.) > 0.)) {
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return fabs(x);
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} else {
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return -fabs(x);
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}
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}
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/* from python 3.1 pymath.c */
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double round(double x)
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{
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double absx, y;
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absx = fabs(x);
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y = floor(absx);
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if (absx - y >= 0.5)
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y += 1.0;
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return copysign(y, x);
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}
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#else /* OpenSuse 11.1 seems to need this. */
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double round(double x);
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#endif
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/* from python 3.1 floatobject.c
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* ndigits must be between 0 and 21 */
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double double_round(double x, int ndigits) {
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double pow1, pow2, y, z;
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if (ndigits >= 0) {
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pow1 = pow(10.0, (double)ndigits);
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pow2 = 1.0;
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y = (x*pow1)*pow2;
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/* if y overflows, then rounded value is exactly x */
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if (!finite(y))
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return x;
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}
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else {
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pow1 = pow(10.0, (double)-ndigits);
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pow2 = 1.0; /* unused; silences a gcc compiler warning */
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y = x / pow1;
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}
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z = round(y);
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if (fabs(y-z) == 0.5)
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/* halfway between two integers; use round-half-even */
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z = 2.0*round(y/2.0);
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if (ndigits >= 0)
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z = (z / pow2) / pow1;
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else
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z *= pow1;
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/* if computation resulted in overflow, raise OverflowError */
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return z;
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}
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