26d375467b
An alternate to D14839, implemented in Python and relying on bpy.data.user_map(). That function gives us a mapping of what ID is referenced by what set of IDs. The inverse of this would also be useful, which is now available from bpy_extras.id_map_utils.get_id_reference_map(). From there, we can use get_all_referenced_ids() to get a set of all IDs referenced by a given ID either directly or indirectly. To get only the direct references, we can simply pass the ID of interest as a key to the dictionary returned from get_id_reference_map(). Reviewed By: mont29 Differential Revision: https://developer.blender.org/D14843
50 lines
1.4 KiB
Python
50 lines
1.4 KiB
Python
# SPDX-License-Identifier: GPL-2.0-or-later
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# <pep8 compliant>
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from typing import Dict, Set
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import bpy
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from bpy.types import ID
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__all__ = (
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"get_id_reference_map",
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"get_all_referenced_ids",
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)
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def get_id_reference_map() -> Dict[ID, Set[ID]]:
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"""Return a dictionary of direct datablock references for every datablock in the blend file."""
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inv_map = {}
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for key, values in bpy.data.user_map().items():
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for value in values:
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if value == key:
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# So an object is not considered to be referencing itself.
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continue
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inv_map.setdefault(value, set()).add(key)
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return inv_map
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def recursive_get_referenced_ids(
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ref_map: Dict[ID, Set[ID]], id: ID, referenced_ids: Set, visited: Set
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):
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"""Recursively populate referenced_ids with IDs referenced by id."""
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if id in visited:
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# Avoid infinite recursion from circular references.
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return
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visited.add(id)
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for ref in ref_map.get(id, []):
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referenced_ids.add(ref)
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recursive_get_referenced_ids(
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ref_map=ref_map, id=ref, referenced_ids=referenced_ids, visited=visited
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)
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def get_all_referenced_ids(id: ID, ref_map: Dict[ID, Set[ID]]) -> Set[ID]:
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"""Return a set of IDs directly or indirectly referenced by id."""
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referenced_ids = set()
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recursive_get_referenced_ids(
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ref_map=ref_map, id=id, referenced_ids=referenced_ids, visited=set()
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)
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return referenced_ids
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